$ \frac{9}{2\sqrt{27}} = \frac{9}{2\sqrt{9 \cdot 3}} = \frac{9}{2\sqrt{9} \cdot \sqrt{3}} = \frac{9}{2\cdot 3 \cdot \sqrt{3}} = \frac{3}{2 \cdot \sqrt{3}} = \frac{3 \cdot \sqrt{3}}{2 \cdot \sqrt{3} \cdot \sqrt{3}}= \frac{3 \cdot \sqrt{3}}{2 \cdot 3} = \sqrt{3}/2 $
pilloeffe ha scritto:Farei così:
$ \frac{9}{2\sqrt{27}} = \frac{9}{2\sqrt{9 \cdot 3}} = \frac{9}{2\sqrt{9} \cdot \sqrt{3}} = \frac{9}{2\cdot 3 \cdot \sqrt{3}} = \frac{3}{2 \cdot \sqrt{3}} = \frac{3 \cdot \sqrt{3}}{2 \cdot \sqrt{3} \cdot \sqrt{3}}= \frac{3 \cdot \sqrt{3}}{2 \cdot 3} = \sqrt{3}/2 $
$9/(2sqrt(27))=9/(2sqrt(9*3))=9/(2sqrt(9)*sqrt(3))=9/(2*3*sqrt(3))=3/(2*sqrt(3))=(3*sqrt(3))/(2*sqrt(3)*sqrt(3))=(3*sqrt(3))/(2*3)=sqrt(3)/2 $
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